tag:blogger.com,1999:blog-28130031636537317452024-02-18T20:31:40.844-08:00Phi, Golden Ratio, 1.618, and US Money...Let's take a look at modern day money as it is used here in the United States, and see if it is proportionally up to the standard set by Mother Earth of ONLY exhibiting the Golden Ratio of 1.618 within the currency's dimensions of internal and external design elements.Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.comBlogger10125tag:blogger.com,1999:blog-2813003163653731745.post-72118107481319166552016-06-24T11:35:00.001-07:002016-06-24T11:35:22.315-07:00What does the Expanded Euclidean Algorithm have to do with RSA Encryption?<iframe allowfullscreen="" frameborder="0" height="344" src="https://www.youtube.com/embed/bLcJhHV7Utk" width="459"></iframe>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-64547205433817352352016-06-24T11:06:00.001-07:002016-06-24T11:06:57.520-07:00Overview of RSA Encryption for Beginners<iframe allowfullscreen="" frameborder="0" height="344" src="https://www.youtube.com/embed/e4c0JG3jRKA" width="459"></iframe>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-38860715877924835402016-06-24T05:02:00.000-07:002016-07-02T12:16:00.191-07:00RSA EncryptionRSA Encryption has been with us since 1987 securing our commercial transactions so that no one steals our private information and thus protects our bank accounts, our ICBM missiles tipped with nuclear warheads pointed at each other (be sure and see the movie: <a href="https://www.google.com/#q=war+games+movie">War Games</a> - with Matthew Broderick, from the 1980s), and a whole bunch of other secrets we find so precious to keep in today's world.<br />
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Needless to say, I'm not a big fan of this scheme. I'd rather be poor (I am already, having lost my son to extreme honesty), then to have several nuclear warheads pointed at me and elsewhere. Without secrets, where would we be?<br />
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The first step in defrocking these secrets is to familiarize our self with how some of the more simpler encryption schemes operate. To this end, I present to you this description I gleaned from watching the following video on YouTube...<br />
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<iframe allowfullscreen="" frameborder="0" height="315" src="https://www.youtube.com/embed/e42kE9XIK7g" width="560"></iframe>
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To aid us in studying his presentation, I have <a href="https://sites.google.com/site/antenaresis/file-cabinet/21%20slides%20highlighting%20RSA%20Encryption%20plus%20a%20demonstration%20in%20JavaScript.zip?attredirects=0&d=1">collected a few slides</a> acting as reminders of <a href="https://www.youtube.com/channel/UCCh8eOn7IubOKnw_TMS-25A">Jordan's</a> main points. Here is the first slide to help us encode and decode a secret message, "Hi"...
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjG2oUuZQWXs-KZFb6MxsGQvqb5x1oLs511yu0Qlfyf11TBbqpbA5fcdDfLHGlhUIskSDZgv6Jh6FJ1oQ9uPCarXd7IWJ6sJUJyaoN4tg_mT_rOU33YjRRsg7D7m-yKQ3GywwUqi5B47_eD/s1600/08+-+Step+4+of+Encryption.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="330" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjG2oUuZQWXs-KZFb6MxsGQvqb5x1oLs511yu0Qlfyf11TBbqpbA5fcdDfLHGlhUIskSDZgv6Jh6FJ1oQ9uPCarXd7IWJ6sJUJyaoN4tg_mT_rOU33YjRRsg7D7m-yKQ3GywwUqi5B47_eD/s640/08+-+Step+4+of+Encryption.JPG" width="640" /></a></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEijaK7esO3s0YoxlLTPLAECgfN8LcdiWrY4C06n6KlahGhvq-2ZM5W-QtCpsQgsggCIoUvOYlzNk_ioR9EuRY9YfVG4-Qi9IGo17eyteNHdtkObO69U7yCqAjh8MR0cv2JQ9ZDt0c7p_kbX/s1600/09+-+Step+5+of+Encryption.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="334" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEijaK7esO3s0YoxlLTPLAECgfN8LcdiWrY4C06n6KlahGhvq-2ZM5W-QtCpsQgsggCIoUvOYlzNk_ioR9EuRY9YfVG4-Qi9IGo17eyteNHdtkObO69U7yCqAjh8MR0cv2JQ9ZDt0c7p_kbX/s640/09+-+Step+5+of+Encryption.JPG" width="640" /></a></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi71TocrDxVHfblScUy72aFE_HmU6znmjcGYiwHEWuktFJ7A0vdk7GD42zHg3gWPHMaaOZjVZS5vS7uJMi4I5_G3BhnHeBAiar8nlrpXJyQnz6fvv3cPjIrrTqoWbX5IHGSVp-yhAYjvWBZ/s1600/10+-+Summary+of+Encryption.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="328" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi71TocrDxVHfblScUy72aFE_HmU6znmjcGYiwHEWuktFJ7A0vdk7GD42zHg3gWPHMaaOZjVZS5vS7uJMi4I5_G3BhnHeBAiar8nlrpXJyQnz6fvv3cPjIrrTqoWbX5IHGSVp-yhAYjvWBZ/s640/10+-+Summary+of+Encryption.JPG" width="640" /></a></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgrjz_lgY8BmrPIowWaPrRIKnb3lNajWbvtzuXHfadLZKjPxVFbHKQrWL1CstsCJOgAsfeIEeaUCwZtHwwmqoyqz83p9ehbSyGhyphenhyphen7EO1ZNcTH64DKcDk36FNtEZdP9eZumeIYNdEuY5cyVD/s1600/12+-+Example+of+Encryption%252C+pt.2.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="278" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgrjz_lgY8BmrPIowWaPrRIKnb3lNajWbvtzuXHfadLZKjPxVFbHKQrWL1CstsCJOgAsfeIEeaUCwZtHwwmqoyqz83p9ehbSyGhyphenhyphen7EO1ZNcTH64DKcDk36FNtEZdP9eZumeIYNdEuY5cyVD/s640/12+-+Example+of+Encryption%252C+pt.2.JPG" width="640" /></a></div>
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgNLcU6WY_RXIP3iQY9nFmEiBXpPd148DHqqSONxuZuzOIbfMs9qM9n_8pj4xeTJkgs06qUufBdsvT-V6ARydHOE8VPBBqvJo4q3bMHt-6cC_Ca790Gptw6SY5Ri-wKRpEOBRxcXTKVFs1Q/s1600/13+-+Example+of+Encryption%252C+pt.3.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="354" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgNLcU6WY_RXIP3iQY9nFmEiBXpPd148DHqqSONxuZuzOIbfMs9qM9n_8pj4xeTJkgs06qUufBdsvT-V6ARydHOE8VPBBqvJo4q3bMHt-6cC_Ca790Gptw6SY5Ri-wKRpEOBRxcXTKVFs1Q/s640/13+-+Example+of+Encryption%252C+pt.3.JPG" width="640" /></a></div>
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To help us understand the mechanics of how this encryption/decryption can actually happen, I've prepared a demonstration in JavaScript which is capable of performing all of the calculations on a scale small enough for it to handle, but not large enough to actually be secure...<br />
<div align="center">
<iframe allowfullscreen="allowfullscreen" frameborder="0" height="350px" src="//jsfiddle.net/Vinyasi/wnvfn361/4/embedded/" width="95%"></iframe>
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All's well, that ends well....Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-21690080360263193352016-06-21T21:11:00.001-07:002016-06-21T21:11:11.617-07:00Overview of an Expanded Version for the Euclidean Algorithm.<iframe allowfullscreen="" frameborder="0" height="344" src="https://www.youtube.com/embed/SE7mKq60iQQ" width="459"></iframe>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-69019109291133755842016-06-21T13:46:00.000-07:002016-06-21T14:29:17.678-07:00The Euclidean Algorithm in Expanded Format<div style="text-align: justify;">
The Euclidean Algorithm for finding the Greatest Common Denominator has always been a linear phenomenon repetitively subtracting the smaller - of a pair of integers - from the larger until a non-negative remainder smaller than the original subtrahend results. With each repetition, the remainder replaces the former subtrahend. This replacement scheme is what makes this style of computation a linear style incapable of breaking out of its limited view of the Golden Number series upon which it is built. This is not surprising, since the protocol for incrementing the Fibonacci series (of: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, etc upon which it is built) is also a linear phenomenon of adding the last number in the series with the integer immediately preceding it. So, the next number after 89 is found by adding it to 55 resulting in 144. To break out of this narrow definition of both Golden Numbers and the Euclidean Algorithm - with no offense intended toward Master Euclid, we must think in terms of a tablature of integers and take an integrated approach towards their computation. Let's begin with the Fibonacci series....</div>
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Instead of defining the Fibonacci series in terms of a series of integers, let's assume two series which increment in parallel with each other. It just so happens that these two parallel series are copies of each other but offset by one position. This is probably why we ignore their uniqueness and assume, for all intents and purposes, that there is only one series of numbers.</div>
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So, series 'a' got a head start over series 'b'. Now, how do we approximate the Golden Ratios of 1.618 and 0.618? Do we use the traditional method of dividing the smaller integer, among two neighboring integers, with its larger neighbor to its right? Or, do we integrate these two parallel series by dividing 'b' into 'a' for one ratio and 'a' into 'b' for another? Let's inspect the following regular pentagon of equal sides and equal angles (each angle is 108°)...</div>
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The answer is, yes we do integrate these two parallel series of integers, but it's not entirely obvious that there isn't only one series. For that premise to my hypothesis, we'll have to wait a little bit.</div>
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This Fibonacci series produces two roots, 1.618 and −0.618, which satisfy the following polynomial...<br />
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<b>X<sup>2</sup> − X<sup>1</sup> − 1 = 0</b></div>
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Now, we'll move on to the next order of Phi, whose ratios
satisfy a third-order polynomial in one unknown, also known as a cubic
polynomial.<br />
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Now, we can approximate the three Golden Ratios of this 3<sup>rd</sup> order Fibonacci series by taking the following proportionate approximations among the diagonals of 'a', 'b', and 'c' of this regular septagon, or seven-sided polygon....<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiYsqNF1lOKuJJSLSUBODG_mLPboS2uR2c_3FKkMf5QQRh3YyjwgLQ7LSsATb7ZeBAmTzXQSuePHv-HYnVmJF_gnkE6g5n45ZwO1OUEwN4AJDFBtvF9AO4JyOS1mjAbYzOkr3j0rO0s8yqq/s1600/3rd+order+approx%252C+35pc.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="262" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiYsqNF1lOKuJJSLSUBODG_mLPboS2uR2c_3FKkMf5QQRh3YyjwgLQ7LSsATb7ZeBAmTzXQSuePHv-HYnVmJF_gnkE6g5n45ZwO1OUEwN4AJDFBtvF9AO4JyOS1mjAbYzOkr3j0rO0s8yqq/s320/3rd+order+approx%252C+35pc.JPG" width="320" /></a></div>
This progressive convergence upon a more accurate approximation results in the following three proportions...<br />
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<div style="text-align: center;">
<b>R<sub>1</sub> = a/c = 2.24697960372</b>
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<b>R<sub>2</sub> = b/a = </b>−<b>0.801937735805</b>
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<b>R<sub>3</sub> = c/b = 0.554958132087</b></div>
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<b> </b>...which satisfy the following polynomial...</div>
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<b>X<sup>3</sup> </b><b>− 2X<sup>2</sup> </b><b>− X<sup>1</sup> + 1 = 0</b></div>
<div style="text-align: center;">
<br /></div>
<div style="text-align: justify;">
<b> </b>Moving on to the fourth order of Golden Series...</div>
<div style="text-align: justify;">
</div>
<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEin-MzEiHY382hAEyh6zlmZgqhUgP-rquBA_AuoaLyDDobefMpnkHg6sl7wyCVNnocNjbPiRlpk-A8AQe4W2RWxd80vIsjasg0yPEhlT4GTFYtZ7KE8D_z6hEDgSs0c0UB3Hd4vZlyoJ-up/s1600/4th+order+progression%252C+50pc%252C+70pc.JPG" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="185" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEin-MzEiHY382hAEyh6zlmZgqhUgP-rquBA_AuoaLyDDobefMpnkHg6sl7wyCVNnocNjbPiRlpk-A8AQe4W2RWxd80vIsjasg0yPEhlT4GTFYtZ7KE8D_z6hEDgSs0c0UB3Hd4vZlyoJ-up/s320/4th+order+progression%252C+50pc%252C+70pc.JPG" width="320" /></a></div>
It's four ratios can be found among the following diagonals of a nonagon, or nine-sided, regular polygon...</div>
<div style="text-align: justify;">
</div>
<div style="text-align: justify;">
</div>
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<div class="separator" style="clear: both; text-align: center;">
<span id="goog_126555080"></span><span id="goog_126555081"></span></div>
<div style="text-align: justify;">
<br /></div>
<div style="text-align: justify;">
It's four approximate roots of a fifth order polynomial in one unknown are...</div>
<div style="text-align: justify;">
<br /></div>
<div style="text-align: center;">
<b>X<sub>1</sub> = a/d = 2.87938524157</b>
<br />
<b>X<sub>2</sub> = b/b = 1</b>
<br />
<b>X<sub>3</sub> = c/a = 0.652703644666</b>
<br />
<b>X<sub>4</sub> = d/c = 0.532088886238</b></div>
<div style="text-align: center;">
<br /></div>
<div style="text-align: justify;">
To be able to make a 4<sup>th</sup> order polynomial in one unknown out of these four numbers will require that two of them are given a negative sign value:
<b><b>−1</b></b> and
<b><b>−0.532088886238</b></b></div>
<div style="text-align: justify;">
<b><br /></b></div>
<div style="text-align: justify;">
We can form this polynomial by multiplying these four values together.
But first, we have to turn them into linear expressions in one
unknown...
<br />
<br />
<b>X<sub>1</sub> = 2.87938524157</b>
<br />
<br />
Subtract <b>2.87938524157</b> from both sides of the equal sign...
<br />
<br />
<b>X<sub>1</sub> − 2.87938524157 = 2.87938524157 − 2.87938524157</b>
<br />
<br />
Yields...
<br />
<b>(X − 2.87938524157) = 0</b>
<br />
<br />
<b>X<sub>2</sub> = −1</b>
<br />
<br />
Add <b>1</b> to both sides of the equal sign...
<br />
<br />
<b>X<sub>2</sub> + 1 = −1 + 1</b>
<br />
<br />
Yields...
<br />
<b>(X + 1) = 0</b>
<br />
<br />
<b>X<sub>3</sub> = 0.652703644666</b>
<br />
<br />
Subtract <b>0.652703644666</b> from both sides of the equal sign...
<br />
<br />
<b>X<sub>3</sub> − 0.652703644666 = 0.652703644666 − 0.652703644666</b>
<br />
<br />
Yields...
<br />
<b>(X − 0.652703644666) = 0</b>
<br />
<br />
<b>X<sub>4</sub> = −0.532088886238</b>
<br />
<br />
Add <b>0.532088886238</b> to both sides of the equal sign...
<br />
<br />
<b>X<sub>4</sub> + 0.532088886238 = −0.532088886238 + 0.532088886238</b>
<br />
<br />
Yields...
<br />
<b>(X + 0.532088886238) = 0</b>
<br />
<br />
Multiplying these four roots together...
<br />
<b>(X − 2.87938524157) × (X + 1) × (X − 0.652703644666) × (X + 0.532088886238) = 0</b>
<br />
<br />
Yields...
<br />
<b>X<sup>4</sup> − 2.87938524157X<sup>3</sup> + 1X<sup>3</sup> − 0.652703644666X<sup>3</sup> + 0.532088886238X<sup>3</sup> <span style="font-family: "wingdings";"></span><span style="font-family: "wingdings";"></span>− 2.87938524157X<sup>2</sup> + 1.87938524157X<sup>2</sup> − 1.53208888624X<sup>2</sup> − 0.652703644666X<sup>2</sup> + 0.532088886238X<sup>2</sup> − 0.347296355334X<sup>2</sup> + 1.87938524157X<sup>1</sup> − 1.53208888624X<sup>1</sup> + 1X<sup>1</sup> − 0.347296355334X<sup>1</sup> + 1 = 0</b>
<br />
<br />
Simplifying further, yields a 4<sup>th</sup> order polynomial in one unknown...
</div>
<div style="text-align: center;">
<b>X<sup>4</sup> </b><b><b>− </b>2X<sup>3</sup> </b><b><b>− </b>3X<sup>2</sup> − X<sup>1</sup> + 1 = 0</b></div>
<div style="text-align: center;">
<br /></div>
<div style="text-align: justify;">
I hope these few examples have convinced you of a progressive tendency towards repeating a basic pattern to a higher and higher degree of Golden Ratios? </div>
<div style="text-align: justify;">
<br /></div>
<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj0hzPFbyGWKMfLUkcJdlaFF6addcPlNKjOxmDEQX9pTwMIL8XpLnPv6fB-hCTS0JdPsPZwHFKMug9HBqGfo_QByvh4Jd5xQu43lMdafKwbUq8yfHRJKPr0UHKEdLuZwyBDm8K-3GwpD_xa/s1600/hr1.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="15" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj0hzPFbyGWKMfLUkcJdlaFF6addcPlNKjOxmDEQX9pTwMIL8XpLnPv6fB-hCTS0JdPsPZwHFKMug9HBqGfo_QByvh4Jd5xQu43lMdafKwbUq8yfHRJKPr0UHKEdLuZwyBDm8K-3GwpD_xa/s320/hr1.png" width="320" /></a></div>
<div style="text-align: justify;">
</div>
<div style="text-align: justify;">
<br /></div>
<div style="text-align: justify;">
I'm going to move on, now, to explain how my expanded hypothesis of the Euclidean Algorithm is deduced from these prior examples...</div>
<div style="text-align: justify;">
<br /></div>
<div style="text-align: justify;">
Let's begin with the first diagram...</div>
<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhAMEbTsb2QroAFfnuzJu-XOTvDwA5Igde6G8ge6TOLogbsuSMMMOr4VeEcMumQRB9eRiCdvasSdiGRx6XqpkXQOjYoxSQDPcGVMz4lvYSdTELwGZy5bJVKj7t_Eqs1uNMX7wIYA4AA5R0z/s1600/2nd+order+progression+and+series%252C+40pc.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="262" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhAMEbTsb2QroAFfnuzJu-XOTvDwA5Igde6G8ge6TOLogbsuSMMMOr4VeEcMumQRB9eRiCdvasSdiGRx6XqpkXQOjYoxSQDPcGVMz4lvYSdTELwGZy5bJVKj7t_Eqs1uNMX7wIYA4AA5R0z/s320/2nd+order+progression+and+series%252C+40pc.jpg" width="320" /></a></div>
<div style="text-align: justify;">
If we were to take the last two numbers in column 11, namely: <b>144</b> and <b>89</b>, we could take the Greatest Common Divisor of these two integers, couldn't we? But how would the operation look the traditional way?</div>
<div style="text-align: justify;">
<br /></div>
<div style="margin-bottom: 0in; text-align: center;">
144 ÷ 89 = 1, with <b>55</b> remaining.</div>
<div style="text-align: center;">
89 ÷ 55 = 1, with <b>34</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
55 ÷ 34 = 1, with <b>21</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
34 ÷ 21 = 1, with <b>13</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
21 ÷ 13 = 1, with <b>8</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
13 ÷ 8 = 1, with <b>5</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
8 ÷ 5 = 1, with <b>3</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
5 ÷ 3 = 1, with <b>2</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
3 ÷ 2 = 1, with <span style="color: red;"><b>1</b></span> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
2 ÷ 1 = 2, with <b>0</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
<span style="color: red;"><b>1</b></span> is the Greatest Common Divisor of 144 and 89.</div>
<br />
<div style="text-align: justify;">
Nobody would want to complicate this simple approach. It's so elegant as it is. But we'll have to in order to prepare ourselves for its subsequent expansion to higher ordered Golden Series of Numbers. Actually, we should have used the modulo operator, rather than division, since we're ignoring the quotient and only paying attention to the remainder...</div>
<div style="margin-bottom: 0in;">
<br /></div>
<div style="margin-bottom: 0in; text-align: center;">
144 % 89 = 1, with <b>55</b> remaining.</div>
<div style="text-align: center;">
89 % 55 = 1, with <b>34</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
55 % 34 = 1, with <b>21</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
34 % 21 = 1, with <b>13</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
21 % 13 = 1, with <b>8</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
13 % 8 = 1, with <b>5</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
8 % 5 = 1, with <b>3</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
5 % 3 = 1, with <b>2</b> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
3 % 2 = 1, with <span style="color: red;"><b>1</b></span> remaining.</div>
<div style="margin-bottom: 0in; text-align: center;">
2 % 1 = 2, with <b>0</b> remaining.<br />
<div style="margin-bottom: 0in; text-align: center;">
<span style="color: red;"><b>1</b></span> is the Greatest Common Divisor of 144 and 89.</div>
<div style="text-align: left;">
<br /></div>
<div style="text-align: left;">
</div>
</div>
<div style="margin-bottom: 0in;">
</div>
<div style="margin-bottom: 0in;">
Here's a demonstration of Euclid's Algorithm from YouTube done in the usual way...<br />
<br />
<div class="separator" style="clear: both; text-align: center;">
<iframe allowfullscreen="" class="YOUTUBE-iframe-video" data-thumbnail-src="https://i.ytimg.com/vi/JUzYl1TYMcU/0.jpg" frameborder="0" height="399" src="https://www.youtube.com/embed/JUzYl1TYMcU?feature=player_embedded" width="480"></iframe></div>
<br />
Now it's time for my method...<br />
<br /></div>
<div align="center">
<table border="2">
<caption>
The Greatest Common Divisor of 144 and 89
</caption>
<tbody>
<tr style="background: #ffeecc;"><th>two integers
</th><th>144
</th><th>89
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>89
</th><th>144
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>89
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>89
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 89
<br />
%0
<br />
<hr />
89
</th><th> 144
<br />
%89
<br />
<hr />
55
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>55
</th><th>89
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>55
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>55
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 55
<br />
%0
<br />
<hr />
55
</th><th> 89
<br />
%55
<br />
<hr />
34
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>34
</th><th>55
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>34
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>34
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 34
<br />
%0
<br />
<hr />
34
</th><th> 55
<br />
%34
<br />
<hr />
21
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>21
</th><th>34
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>21
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>21
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 21
<br />
%0
<br />
<hr />
21
</th><th> 34
<br />
%21
<br />
<hr />
13
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>13
</th><th>21
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>13
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>13
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 13
<br />
%0
<br />
<hr />
13
</th><th> 21
<br />
%13
<br />
<hr />
8
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>8
</th><th>13
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>8
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>8
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 8
<br />
%0
<br />
<hr />
8
</th><th> 13
<br />
%8
<br />
<hr />
5
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>5
</th><th>8
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>5
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>5
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 5
<br />
%0
<br />
<hr />
5
</th><th> 8
<br />
%5
<br />
<hr />
3
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>3
</th><th>5
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>3
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>3
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 3
<br />
%0
<br />
<hr />
3
</th><th> 5
<br />
%3
<br />
<hr />
2
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>2
</th><th>3
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>2
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>2
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 2
<br />
%0
<br />
<hr />
2
</th><th> 3
<br />
%2
<br />
<hr />
1
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>1
</th><th>2
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>1
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>1
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and take their modulo
</th><th> 1
<br />
%0
<br />
<hr />
<span style="color: red;"><big>1</big></span>
</th><th> 2
<br />
%1
<br />
<hr />
0
</th></tr>
</tbody>
</table>
</div>
</div>
<div style="text-align: center;">
<span style="color: red;"><b>1</b></span> is the Greatest Common Divisor of 144 and 89.
</div>
<div style="text-align: justify;">
<br /></div>
<div style="text-align: justify;">
I call this process unzipping, because I'm reducing 144 and 89 in the same manner that created them in the first place...</div>
<div class="separator" style="clear: both; text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhAMEbTsb2QroAFfnuzJu-XOTvDwA5Igde6G8ge6TOLogbsuSMMMOr4VeEcMumQRB9eRiCdvasSdiGRx6XqpkXQOjYoxSQDPcGVMz4lvYSdTELwGZy5bJVKj7t_Eqs1uNMX7wIYA4AA5R0z/s1600/2nd+order+progression+and+series%252C+40pc.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="262" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhAMEbTsb2QroAFfnuzJu-XOTvDwA5Igde6G8ge6TOLogbsuSMMMOr4VeEcMumQRB9eRiCdvasSdiGRx6XqpkXQOjYoxSQDPcGVMz4lvYSdTELwGZy5bJVKj7t_Eqs1uNMX7wIYA4AA5R0z/s320/2nd+order+progression+and+series%252C+40pc.jpg" width="320" /></a></div>
<div style="text-align: justify;">
By analyzing the manner in which these golden numbers zip themselves up and unzip themselves back down, we see that they have a very unique identity in that their collective quotients are always <b>1</b> and their remainders yield the prior set of Fibonacci numbers. Try and do that with non-Golden numbers!<br />
<br />
We'll move on to the cubic order of Golden Numbers and see this same pattern repeat itself. And since the standardized, conventional method of performing the Euclidean Algorithm won't apply to this scenario, I must dispense with it and use my own... <br />
<br />
Summary,
<br />
It can be said of Golden Numbers, of any degree Golden Polynomial for which their Golden Ratios are the solutions, that their unique property is that they close themselves. Only a Golden Number can be added to another Golden Number, from the same set, to build up a Golden Series. And only a Golden Number from the same set can be subtracted from another Golden Number to produce another smaller Golden Number from the same set.
<br />
<br />
It must also be emphasized that division is not occuring here, only repetitive subtraction, since we're not interested in the quotient – we're only interested in the remainder. Since the modulo operator is equivalent to repetitive subtraction, we use it to reduce integers during performance of the Euclidean Algorithm.
<br />
<br />
But we're engaging a special case, here, of using only Golden Numbers – not any integer – in the performance of the Euclidean Algorithm to find the Greatest Common Divisor among them. So, we need not utilize the services of the modulo operator. We may replace it with subtraction since we'll only be performing repetitive subtraction once yielding a quotient of one.<br />
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<div style="text-align: center;">
<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiesU1JXioks-Mtts6ALlVdLJiCyZFJgob_OCza41zTc67jkx9jiCkTiEd8wSHLVBG1iKEFQFAO1Cz_mGGrCArQTzfY1lC5KyoEM3ZaThkFCVjN10xVUGV4wKOUAB-OqnQGizL_WF4VKI51/s1600/3rd+order+progression+and+series%252C+40pc%252C+70pc.JPG" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="239" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiesU1JXioks-Mtts6ALlVdLJiCyZFJgob_OCza41zTc67jkx9jiCkTiEd8wSHLVBG1iKEFQFAO1Cz_mGGrCArQTzfY1lC5KyoEM3ZaThkFCVjN10xVUGV4wKOUAB-OqnQGizL_WF4VKI51/s320/3rd+order+progression+and+series%252C+40pc%252C+70pc.JPG" width="320" /></a> </div>
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<div align="center">
<table border="2">
<caption>
The Greatest Common
<br />
Divisor of 636, 793 and 353
</caption>
<tbody>
<tr style="background: #ffeecc;"><th>three integers
</th><th>636
</th><th>793
</th><th>353
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>353
</th><th>636
</th><th>793
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>353
</th><th>636
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>353
</th><th>636
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th>353
<br />
− 0
<br />
<hr />
353
</th><th> 636
<br />
−353
<br />
<hr />
283
</th><th> 793
<br />
−636
<br />
<hr />
157
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>157
</th><th>283
</th><th>353
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>157
</th><th>283
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>157
</th><th>283
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th>157
<br />
− 0
<br />
<hr />
157
</th><th> 283
<br />
−157
<br />
<hr />
126
</th><th> 353
<br />
−283
<br />
<hr />
70
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>70
</th><th>126
</th><th>157
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>70
</th><th>126
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>70
</th><th>126
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 70
<br />
− 0
<br />
<hr />
70
</th><th> 126
<br />
− 70
<br />
<hr />
56
</th><th> 157
<br />
−126
<br />
<hr />
31
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>31
</th><th>56
</th><th>70
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>31
</th><th>56
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>31
</th><th>56
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 31
<br />
− 0
<br />
<hr />
31
</th><th> 56
<br />
− 31
<br />
<hr />
25
</th><th> 70
<br />
− 56
<br />
<hr />
14
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>14
</th><th>25
</th><th>31
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>14
</th><th>25
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>14
</th><th>25
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 14
<br />
− 0
<br />
<hr />
14
</th><th> 25
<br />
− 14
<br />
<hr />
11
</th><th> 31
<br />
− 25
<br />
<hr />
6
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>6
</th><th>11
</th><th>14
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>6
</th><th>11
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>6
</th><th>11
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 6
<br />
− 0
<br />
<hr />
6
</th><th> 11
<br />
− 6
<br />
<hr />
5
</th><th> 14
<br />
− 11
<br />
<hr />
3
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>3
</th><th>5
</th><th>6
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>3
</th><th>5
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>3
</th><th>5
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 3
<br />
− 0
<br />
<hr />
3
</th><th> 5
<br />
− 3
<br />
<hr />
2
</th><th> 6
<br />
− 5
<br />
<hr />
1
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>1
</th><th>2
</th><th>3
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>1
</th><th>2
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>1
</th><th>2
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 1
<br />
− 0
<br />
<hr />
1
</th><th> 2
<br />
− 1
<br />
<hr />
1
</th><th> 3
<br />
− 2
<br />
<hr />
1
</th></tr>
<tr style="background: #ddddff;"><th>sort from left to right
</th><th>1
</th><th>1
</th><th>1
</th></tr>
<tr style="background: #ddffdd;"><th>shift to the right
</th><th>*
</th><th>1
</th><th>1
</th></tr>
<tr style="background: #ddddff;"><th>replace * with a zero
</th><th>0
</th><th>1
</th><th>1
</th></tr>
<tr style="background: #ffeecc;"><th>stack the two rows of integers,
<br />
the 'sort' on top of 'replace',
<br />
and perform subtraction
</th><th> 1
<br />
− 0
<br />
<hr />
<span style="color: red;"><big>1</big></span>
</th><th> 1
<br />
− 1
<br />
<hr />
0
</th><th> 1
<br />
− 1
<br />
<hr />
0
</th></tr>
</tbody>
</table>
<span style="color: red;"><b>1</b></span> is the Greatest Common Divisor of 636, 793 and 353.
</div>
<br />
In conclusion,
<br />
The study of the Infinite Range of Golden Ratios, and the Golden Numbers which spawn them, yields a fuller appreciation for the Euclidean Algorithm and a more efficient method for discovering the Greatest Common Divisor among any quantity of integers.
<br />
<br />
Here are some JavaScripts to bring my method to life! This first one generates a few integers at random and multiplies them against another small integer to find their Greatest Common Divisor.</div>
<div style="text-align: center;">
<iframe allowfullscreen="allowfullscreen" frameborder="0" src="https://jsfiddle.net/Vinyasi/xwdh0dfz/1/embedded/" style="height: 350px; width: 95%;"></iframe>
</div>
<div style="text-align: justify;">
<br />
This next JavaScript will accept any quantity of non-zero integers so long as they are not equal each other...</div>
<div style="text-align: center;">
<iframe allowfullscreen="allowfullscreen" frameborder="0" src="https://jsfiddle.net/Vinyasi/nwLc8qsg/2/embedded" style="height: 350px; width: 95%;"></iframe>
</div>
<br />
<br />Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-29256782544110439842016-06-02T19:19:00.001-07:002019-12-19T21:26:12.272-08:00Introduction to the Infinite Range of Golden RatioUnbeknownst to <i>all</i> mathematicians, the Golden Ratio is infinite in scope <br />
<br />
<a href="http://vinyasi.info/Infinite%20Range%20of%20Golden%20Ratios/">Introduction to the Infinite Range of Golden Ratio</a>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-82260446925383844182012-04-21T10:04:00.000-07:002012-04-21T10:04:35.405-07:00A Few References...<ul><li><a href="http://www.mlahanas.de/Greeks/Pentagon.htm" target="_blank">The Irrationality of the Pentagon and the Pentagram</a>, by Michael Lahanas</li>
</ul>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-70857114865816880572012-04-16T11:13:00.008-07:002012-04-21T09:15:21.626-07:00Plastic Money Approximates the Golden Ratio of 1.618It is not necessary to modify the proportions of various plastic cards, namely: debit cards, credit cards, gift cards, or a state California license-to-drive card, since they all are of the same dimensions of 8.6 cm long by 5.4 cm high (or wide). 8.6 cm ÷ 5.4 cm = 1.59259.<br />
<br />
<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh7tEu630kPkDK6ZyHiEl3UCvy8Uvsit605gkR_bzmRTkVMYf4Va5lcUXSPHh_lfN-YwjK01_eqADUmQe33gt5t3UFvKR2X_E425A430O4ZlREXFLM_Td0XOiLE4rKdo4HfVEyRvmct_WO2/s1600/Chevron_Gift_Card.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh7tEu630kPkDK6ZyHiEl3UCvy8Uvsit605gkR_bzmRTkVMYf4Va5lcUXSPHh_lfN-YwjK01_eqADUmQe33gt5t3UFvKR2X_E425A430O4ZlREXFLM_Td0XOiLE4rKdo4HfVEyRvmct_WO2/s1600/Chevron_Gift_Card.jpg" /></a></div><br />
<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgrpN2zPp1NFjAEnrddrTk7dcFoRG37v8euDzsUQqsLq3IFGwq7C60j7qbRZlfaUgTFqzL-l93OzqN7_hBL1NGoZQ4huI_2Av1iS5uN_lTxWyl63zDZdeXblYINuUaE4uY9GfyMzYyKxAGZ/s1600/Ralphs_Gift_Card-v1.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgrpN2zPp1NFjAEnrddrTk7dcFoRG37v8euDzsUQqsLq3IFGwq7C60j7qbRZlfaUgTFqzL-l93OzqN7_hBL1NGoZQ4huI_2Av1iS5uN_lTxWyl63zDZdeXblYINuUaE4uY9GfyMzYyKxAGZ/s1600/Ralphs_Gift_Card-v1.jpg" /></a></div><br />
Since Federal Reserve Notes exhibit the Pell ratio of 2.35 (2.348 = 15.5 cm long ÷ 6.6 cm long), then it appears to me that our money supply has already been subliminally programed to encourage us to favor the use of plastic over paper. <em>{Digital money, ie credit cards, debit cards, personal checks, and bank wire transfers and the like, comprise 98% of the economy.}</em><br />
<br />
There is at least one exception, notably...<br />
<br />
<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhijGmlUrP64mPUCANLz-6LEsE2m07FzDt08YeaduOWgjnnxbXzy-9_WgFIvtP_37OfWEwf1dcgxDvqQzSs5U82jgilY3ebtXFQIn6OvVP2WpG5uqEHsPwx6d8InCrVtT7xdRI7UDQ9x7_m/s1600/Target_gift_card-resized2.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhijGmlUrP64mPUCANLz-6LEsE2m07FzDt08YeaduOWgjnnxbXzy-9_WgFIvtP_37OfWEwf1dcgxDvqQzSs5U82jgilY3ebtXFQIn6OvVP2WpG5uqEHsPwx6d8InCrVtT7xdRI7UDQ9x7_m/s1600/Target_gift_card-resized2.jpg" /></a></div><div class="separator" style="clear: both; text-align: center;"></div><br />
<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgwosuH_YYE0WUkQ0qLux-deKJBn5EyZse0fv8OaIh49PyU9wNd2qVEvOPtNHk6cGYldasYUGAbzVES5T6L8sRuVZnOisXLyMBKhybgx_xituZFER2gaHyKliDRGS3u5jP2wUEzLpwuTA4g/s1600/Target_gift_card_side-measurement-resized2.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgwosuH_YYE0WUkQ0qLux-deKJBn5EyZse0fv8OaIh49PyU9wNd2qVEvOPtNHk6cGYldasYUGAbzVES5T6L8sRuVZnOisXLyMBKhybgx_xituZFER2gaHyKliDRGS3u5jP2wUEzLpwuTA4g/s1600/Target_gift_card_side-measurement-resized2.jpg" /></a></div><div class="separator" style="clear: both; text-align: center;"></div><br />
This gift card from Target store, exhibited above, has a length of 8.6 cm and a height (or, width) of 7 cm. If we take 8.6 and divide it by 7, then the outcome is 1.2285714. If we then multiply this result by a factor of two, then the result is 2.4571429. This is a close approximation of the Pell ratio. I may be wrong, but I think I recall <a href="http://www.target.com/c/GiftCards/-/N-5xsxu">another version of a Target gift card</a> in the proportion of a golden rectangle sold within Target stores?<br />
<br />
Digital money is not a totally bad thing...<br />
<br />
If we want to further improve upon the value of plastic money, we may go further by <a href="http://www.libertygold.co.nz/?rewards=6e0b085e-3f4b-4b54-edc7-da390186c20e">backing it up</a> with <em>real value:</em> commodities/products or services. This is not the case with Federal Reserve Notes. If the economy crashed tomorrow, Federal Reserve Notes would not have any purchasing power, and you wouldn't be able to purchase anything – no matter how desperate you were. <em>Although you could pay your debts to the banks with them, but don't count on any substantial portion of your debt being paid off with them since they would in all likelihood be worth less than the value of a postage stamp; actually, you'd be better off paying your debts with a postage stamp if this was acceptable to the other party negotiating the payment of your debt to them!</em> {As you may already know, Federal Reserve Notes are not backed up with anything other than more Federal Reserve Notes.}Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com2tag:blogger.com,1999:blog-2813003163653731745.post-83190414494854177662012-04-09T13:37:00.101-07:002012-04-14T11:35:48.919-07:00Eliminate Dead Presidents!<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg4F_VIB1Yu8HldnfW-fF2uYp4NQ37mkIhe2uEJYkv-e05pXlt9GCbuwKG4a1xAsGqCHRxoLMOytG4yFX1hT_vKeRLQ97g2UldMuuAvslmJcLrdoisUs78cYZAN5V8W7IW6PNa5laJ6c1Zi/s1600/dead_presidents-50%25.jpg" imageanchor="1" style="clear: right; float: right; margin-bottom: 1em; margin-left: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg4F_VIB1Yu8HldnfW-fF2uYp4NQ37mkIhe2uEJYkv-e05pXlt9GCbuwKG4a1xAsGqCHRxoLMOytG4yFX1hT_vKeRLQ97g2UldMuuAvslmJcLrdoisUs78cYZAN5V8W7IW6PNa5laJ6c1Zi/s1600/dead_presidents-50%25.jpg" /></a></div><em><span style="color: #cc0000;">{Please refer to the <a href="http://goldenfed.blogspot.com/2012/04/golden-fed-money-via-golden-ratiomean.html">very first post below</a>. This post builds on it by extending the idea further.}</span></em><br />
<br />
There is another way to fold Federal Reserve Notes that creates a golden rectangle, preserves the two serial numbers on its face in their entirety, and eliminates the image of the dead president in its center. It's a fan-fold over the president's picture bringing the two ends closer together. This is accomplished in a manner somewhat similar to how MAD magazine describes how to <a alt="MAD Magazine Fold-ins, Past & Present" href="http://www.nytimes.com/interactive/2008/03/28/arts/20080330_FOLD_IN_FEATURE.html">fold their back page</a> to create a new image, but slightly different. Here's how to do it...<br />
<br />
<strong><em><span style="color: blue;"><u>THE TAPE METHOD</u></span></em></strong><br />
For a one dollar bill:<br />
<br />
<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEieFQrRtEK_ryXHTKkKZheveAWuU-wsr4E0eurS6Z6k7t4fMQcTUrwWvHhxWpraeDAz3lEVjRNpAV73ixhSkWAGyFWDStK2TS5_cIjwE4XbGA4szrxnZ5-CLPLPWdTebsVPd-B10xA5Mwg-/s1600/one_dollar-no_prez.jpg" imageanchor="1"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEieFQrRtEK_ryXHTKkKZheveAWuU-wsr4E0eurS6Z6k7t4fMQcTUrwWvHhxWpraeDAz3lEVjRNpAV73ixhSkWAGyFWDStK2TS5_cIjwE4XbGA4szrxnZ5-CLPLPWdTebsVPd-B10xA5Mwg-/s1600/one_dollar-no_prez.jpg" /></a></div><br />
<a href="http://goldenfed.blogspot.com/2012/04/eliminate-dead-presidents.html#tape-method" name="tape-method">1. Make a right-fold</a> nearest to the left-most edge of the left-most alpha-character of the right set of serial numbers, folding the right end over towards the backside. In this example pictured above, this fold is performed alongside the left-most edge of the capital letter "L" of the right serial number, "L 83780228 G".<br />
<br />
2. Now, make a left-fold nearest the right-most edge of the right-most alpha-character of the left set of serial numbers, folding the left end over towards the backside. In this example, the fold is performed alongside the right-most edge of the capital letter "G" of the left serial number, "L 83780228 G". This fold may also be guided by folding inbetween the letters "I" and "T" in the phrase along the top of the note, "<span style="background-color: #b4a7d6;">THE UNI</span><span style="background-color: #ffe599;">TED STATES OF AMERICA</span>".<br />
<br />
<a href="http://goldenfed.blogspot.com/2012/04/eliminate-dead-presidents.html#step3" name="step3">3. Now,</a> bring these two folds together to meet alongside each other. Check this new shorter length of the remaining bill visible to sight. It should be around 10.8 cm; 10.7 cm is the ideal, since the height is 6.6 cm and 10.7 cm divided by 6.6 cm is 1.62 – very close to approximating 1.618. But at this new length of 10.8 cm, the ratio will instead be 1.636 – not too far off and preserving the entire appearance of both serial numbers to keep this legal and satisfy the bank's criteria for accepting this note.<br />
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<table align="center" cellpadding="0" cellspacing="0" class="tr-caption-container" style="margin-left: auto; margin-right: auto; text-align: center;"><tbody>
<tr><td style="text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgPN2_eOowQx-eu2r3IaoQNuowvtqeEqhoHPxr4KPA629oKb5yT9Ax5lttGxOskzHxX2culW8N7dARdoCXh6kJbuNB1cy6DQoftWv4ONJ5ep6sY0SvnSl_CGjzSCgi2GS_DOQzy6xn095m-/s1600/omega.jpg" imageanchor="1" style="margin-left: auto; margin-right: auto;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgPN2_eOowQx-eu2r3IaoQNuowvtqeEqhoHPxr4KPA629oKb5yT9Ax5lttGxOskzHxX2culW8N7dARdoCXh6kJbuNB1cy6DQoftWv4ONJ5ep6sY0SvnSl_CGjzSCgi2GS_DOQzy6xn095m-/s200/omega.jpg" width="200" /></a></td></tr>
<tr><td class="tr-caption" style="text-align: center;">This image is from the "The Staple Method" below, and is being used to illustrate the Omega shape described in Step 4.</td></tr>
</tbody></table>4. Cut a piece of clear tape a little longer than the height of the note. Tape one fold with half of the width of the tape running the piece of tape vertically up and down the length of the fold along the outside of the fold facing away from the image of the dead president. Bring the remaining fold alongside the taped fold, and tape the two folds together using the remaining half-width of the tape. You should have a loop of Federal Reserve Note so that if you were to look at this note from the edge, the note with its loop would like the Greek letter Omega.<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEitwLCAu9rHx4hAWVeYH26HoOoZjD-kleMu1W0lC6DWRCCOuzvB7ulTcrI3nfFsFmWY0ys09jVsTvMrRS-y5wDqiduTCHyY6VFmNoUpXlWSpMY8opnrIsFlvqsoTTt7w0kmn4SNDzS1Tb5D/s1600/back_loop.jpg" imageanchor="1"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEitwLCAu9rHx4hAWVeYH26HoOoZjD-kleMu1W0lC6DWRCCOuzvB7ulTcrI3nfFsFmWY0ys09jVsTvMrRS-y5wDqiduTCHyY6VFmNoUpXlWSpMY8opnrIsFlvqsoTTt7w0kmn4SNDzS1Tb5D/s200/back_loop.jpg" width="200" /></a> <a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_Ub7wLdI2Nh8cjSnZfvSKMaSemCB532izaZOlrwbFWV8wPasINkA72qQKw24_ZcSkv0SBehGyzjm8VONzAxbi4SX8tKNfwgMmR2QfV5coiVIIfw19vLN26sFzqaV_RndDlUQUm6LTX7o6/s1600/flattened_backside.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_Ub7wLdI2Nh8cjSnZfvSKMaSemCB532izaZOlrwbFWV8wPasINkA72qQKw24_ZcSkv0SBehGyzjm8VONzAxbi4SX8tKNfwgMmR2QfV5coiVIIfw19vLN26sFzqaV_RndDlUQUm6LTX7o6/s200/flattened_backside.jpg" width="200" /></a></div>These images are from the "The Staple Method" below, and are intended to illustrate flattening the Omega loop on the backside.<br />
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5. Turn this bill over so that its backside is facing up and squash this loop against the two taped folds and crease the two edges of this flattened loop with your thumbnail. Run your thumbnail up and down these creases against the table top upon which this note is resting on. There should be a little bit of tape over-hanging both the top and bottom edges of the note. Carefully bend these remaining bits of tape over towards the backside of the note, and give them a nice crease.<br />
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Voila! You're finished!<br />
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Now, double-check the new length of this shortened note for similarity to 10.7 cm, or 10.8 cm, or thereabouts.<br />
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For five dollar bills, the placement of each fold is slightly different than their placement for a one dollar bill...<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhBynbs-OWp_SJMkytDA8xrMfbE_mQTTLN4OyNGhDFZ6c9HfOvBb5-LAR7zQfXtJ6OwhweA6S0UdZh9j-6kDuURcNalbLIGr6XlKRgBxkIN635uFeTljLV__ZGnU6G5ezkqIP0kHzltuuXL/s1600/five_dollars-no_prez.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhBynbs-OWp_SJMkytDA8xrMfbE_mQTTLN4OyNGhDFZ6c9HfOvBb5-LAR7zQfXtJ6OwhweA6S0UdZh9j-6kDuURcNalbLIGr6XlKRgBxkIN635uFeTljLV__ZGnU6G5ezkqIP0kHzltuuXL/s1600/five_dollars-no_prez.jpg" /></a></div><br />
1. Make a right-fold along the left side of the vertical stem of the capital letter "T" in the phrase, "THE UNITED STATES OF AMERICA". This should cut off a little bit of the left-horizontal top to this letter, and leave a little bit of space to the left of the whole right serial number. In this example pictured above, this right fold is slightly away from the left-most edge of the right serial number, "IL 25025502 C".<br />
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2. Now make a left-fold immediately to the right of the last capital letter of the left serial number. In this example, this fold is to the immediate right of the capital letter "C" of "IL 25025502 C".<br />
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3-5. Repeat steps <a href="http://goldenfed.blogspot.com/2012/04/eliminate-dead-presidents.html#step3">three through five above</a>.<br />
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Folding a five dollar bill should bring the new length closer to the goal, either 10.7 cm or 10.8 cm.<br />
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<strong><em><span style="color: blue;"><u>THE STAPLE METHOD</u></span></em></strong><br />
For a one dollar bill:<br />
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Follow <a href="http://goldenfed.blogspot.com/2012/04/eliminate-dead-presidents.html#tape-method">steps one through three described above</a> for using "The Tape Method".<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj8UKaCdCOOK4MCenVyUDKoUekIgKy_V70PFMJhgNIlCSGiLlfyFt-r_DcAYCVL5fXk2tlqSTMVmPXhFkKD-WDmUJjLWWE8bUvRwUrZXRBFtfmmwfpqrRx8Y0piOEmM5qoAcuMGKpPUcSpi/s1600/front_tape.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj8UKaCdCOOK4MCenVyUDKoUekIgKy_V70PFMJhgNIlCSGiLlfyFt-r_DcAYCVL5fXk2tlqSTMVmPXhFkKD-WDmUJjLWWE8bUvRwUrZXRBFtfmmwfpqrRx8Y0piOEmM5qoAcuMGKpPUcSpi/s200/front_tape.jpg" width="200" /></a><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgPN2_eOowQx-eu2r3IaoQNuowvtqeEqhoHPxr4KPA629oKb5yT9Ax5lttGxOskzHxX2culW8N7dARdoCXh6kJbuNB1cy6DQoftWv4ONJ5ep6sY0SvnSl_CGjzSCgi2GS_DOQzy6xn095m-/s1600/omega.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgPN2_eOowQx-eu2r3IaoQNuowvtqeEqhoHPxr4KPA629oKb5yT9Ax5lttGxOskzHxX2culW8N7dARdoCXh6kJbuNB1cy6DQoftWv4ONJ5ep6sY0SvnSl_CGjzSCgi2GS_DOQzy6xn095m-/s200/omega.jpg" width="200" /></a></div><br />
4. Cut a very small piece of tape (I use tan-colored masking tape in this example pictured above). Tape one fold with half of the tape running the piece of tape across the fold facing away from the image of the dead president. Bring the remaining fold alongside the taped fold, and tape the two folds together using the remaining half of the tape. You should have a loop of Federal Reserve Note so that if you were to look at this note from the edge, the note with its loop would like the Greek letter Omega.<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_Ub7wLdI2Nh8cjSnZfvSKMaSemCB532izaZOlrwbFWV8wPasINkA72qQKw24_ZcSkv0SBehGyzjm8VONzAxbi4SX8tKNfwgMmR2QfV5coiVIIfw19vLN26sFzqaV_RndDlUQUm6LTX7o6/s1600/flattened_backside.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEh_Ub7wLdI2Nh8cjSnZfvSKMaSemCB532izaZOlrwbFWV8wPasINkA72qQKw24_ZcSkv0SBehGyzjm8VONzAxbi4SX8tKNfwgMmR2QfV5coiVIIfw19vLN26sFzqaV_RndDlUQUm6LTX7o6/s200/flattened_backside.jpg" width="200" /></a><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEitwLCAu9rHx4hAWVeYH26HoOoZjD-kleMu1W0lC6DWRCCOuzvB7ulTcrI3nfFsFmWY0ys09jVsTvMrRS-y5wDqiduTCHyY6VFmNoUpXlWSpMY8opnrIsFlvqsoTTt7w0kmn4SNDzS1Tb5D/s1600/back_loop.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="150" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEitwLCAu9rHx4hAWVeYH26HoOoZjD-kleMu1W0lC6DWRCCOuzvB7ulTcrI3nfFsFmWY0ys09jVsTvMrRS-y5wDqiduTCHyY6VFmNoUpXlWSpMY8opnrIsFlvqsoTTt7w0kmn4SNDzS1Tb5D/s200/back_loop.jpg" width="200" /></a></div><br />
5. Turn this bill over so that its backside is facing up and squash this loop against the two taped folds and crease the two edges of this flattened loop with your thumbnail. Run your thumbnail up and down these creases against the table top upon which this note is resting on. There should be a little bit of tape over-hanging both the top and bottom edges of the note. Carefully bend these remaining bits of tape over towards the backside of the note, and give them a nice crease.<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgGnB1Z4fnC7WGFzkdMS2oJmnSyO-jkPMaa6TCsFiiaecGwkgrRXXrO2h56bm1PTpxgJaZkDU8EjqJ9DolSiV8LFa7LhJYuENnI4j5y9DwHSAB8BC2dasbyjwr2uACD9hElpDUMl_436BQY/s1600/two_staples_+_tape.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgGnB1Z4fnC7WGFzkdMS2oJmnSyO-jkPMaa6TCsFiiaecGwkgrRXXrO2h56bm1PTpxgJaZkDU8EjqJ9DolSiV8LFa7LhJYuENnI4j5y9DwHSAB8BC2dasbyjwr2uACD9hElpDUMl_436BQY/s1600/two_staples_+_tape.jpg" /></a></div><div class="separator" style="clear: both; text-align: center;"><br />
</div> 6. If you look closely at the image above, you'll see the little piece of masking tape in the center of the fold, a staple towards the top of the note and beneath the shortened phrase: "FED NOTE" and above another shortened phrase: "THE UNI AMERICA", and a second staple towards the bottom of the note directly covering the two letters: "O R".<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjgEnoTUh-OvYdK82UauPB7nxYOEKl6VK9FlnK-SqVwpCrH73SfnDIQ9VkHzJIR5AA-nx78sz100BtcyTrhPE9CT4UgukxNux2vxnzmgpqoJg2EawoXBoGTizZnAfJt1TMTI7fF_o8jr0FM/s1600/three_staples.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjgEnoTUh-OvYdK82UauPB7nxYOEKl6VK9FlnK-SqVwpCrH73SfnDIQ9VkHzJIR5AA-nx78sz100BtcyTrhPE9CT4UgukxNux2vxnzmgpqoJg2EawoXBoGTizZnAfJt1TMTI7fF_o8jr0FM/s1600/three_staples.jpg" /></a></div><br />
7. This image above shows the finished product with a third staple in the center of the fold replacing the little piece of masking tape. Notice how the length of this newly formed golden rectangle is not quite the ideal of 10.7 cm? Oh, well.... There is a solution...<br />
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8. Snip a little bit off one or both edges, left or right side. Either one or two millimeters will do the job.<br />
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<table align="center" cellpadding="0" cellspacing="0" class="tr-caption-container" style="margin-left: auto; margin-right: auto; text-align: center;"><tbody>
<tr><td style="text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhV0SHpEf4ZFEqcZe0pis7kvowVQwZTR7hWpElgOufMw89I7QJSOHvNCElh19RjP74e934PxD0G-XFKWbA96DLiHPr88gmvK-HeWwFfSPS7s6H4nTPL8uLnoC5u1t2MD9WE7LPTACxmhKKt/s1600/$1_snipped-with-tape.jpg" imageanchor="1" style="margin-left: auto; margin-right: auto;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhV0SHpEf4ZFEqcZe0pis7kvowVQwZTR7hWpElgOufMw89I7QJSOHvNCElh19RjP74e934PxD0G-XFKWbA96DLiHPr88gmvK-HeWwFfSPS7s6H4nTPL8uLnoC5u1t2MD9WE7LPTACxmhKKt/s1600/$1_snipped-with-tape.jpg" /></a></td></tr>
<tr><td class="tr-caption" style="text-align: center;">Notice how the right-edge has had four millimeters snipped off? This is the "TAPED" version.</td></tr>
</tbody></table><br />
<table align="center" cellpadding="0" cellspacing="0" class="tr-caption-container" style="margin-left: auto; margin-right: auto; text-align: center;"><tbody>
<tr><td style="text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgp7pJfWW63c_RBmWjKfJZVoo3_IhZdOeuYpgkPBDjJX_RAyWR5M8sTnHm1whIh5RPIuRwDXWFuPHZe50O0dvVV4dLlWfChiWflIkud1hehgABtQ5Nz3j1oEn4QpnLRVHioc7YcgiDD0BmF/s1600/$1_snipped-with-staples.jpg" imageanchor="1" style="margin-left: auto; margin-right: auto;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgp7pJfWW63c_RBmWjKfJZVoo3_IhZdOeuYpgkPBDjJX_RAyWR5M8sTnHm1whIh5RPIuRwDXWFuPHZe50O0dvVV4dLlWfChiWflIkud1hehgABtQ5Nz3j1oEn4QpnLRVHioc7YcgiDD0BmF/s1600/$1_snipped-with-staples.jpg" /></a></td></tr>
<tr><td class="tr-caption" style="text-align: center;">This is the "STAPLED" version. It has had two millimeters snipped off of both edges, left and right.</td></tr>
</tbody></table>It is not necessary to snip anything off of a five dollar version since there is enough abundant space inbetween the inside edge of both serial numbers that is greater than what is required for doing this style of folding notes to create a golden rectangle. Notice the excess space, in the example below, to the immediate left of the right-most serial number.<br />
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<a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhBynbs-OWp_SJMkytDA8xrMfbE_mQTTLN4OyNGhDFZ6c9HfOvBb5-LAR7zQfXtJ6OwhweA6S0UdZh9j-6kDuURcNalbLIGr6XlKRgBxkIN635uFeTljLV__ZGnU6G5ezkqIP0kHzltuuXL/s1600/five_dollars-no_prez.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhBynbs-OWp_SJMkytDA8xrMfbE_mQTTLN4OyNGhDFZ6c9HfOvBb5-LAR7zQfXtJ6OwhweA6S0UdZh9j-6kDuURcNalbLIGr6XlKRgBxkIN635uFeTljLV__ZGnU6G5ezkqIP0kHzltuuXL/s1600/five_dollars-no_prez.jpg" /></a>Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0tag:blogger.com,1999:blog-2813003163653731745.post-886983257566096272012-04-08T01:03:00.025-07:002012-04-21T09:19:46.558-07:00Federal Reserve Notes and the Golden Ratio of 1.618<div class="separator" style="clear: both; text-align: left;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiBjMCKv1vVf6yZlOKTFocE_xSvA3153M9cylNfvw74H_pCcCMwhoWt6avr97chbqgt70D_Zdstlu0SVOtF2MAbUgmDVxUE8QLzZa-b5XIZudlW_mIR7FKuXduCFZSGJ79B5MEg3OWYM9jG/s1600/one_dollar-50%25.jpg" imageanchor="1" style="clear: right; float: right; margin-bottom: 1em; margin-left: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiBjMCKv1vVf6yZlOKTFocE_xSvA3153M9cylNfvw74H_pCcCMwhoWt6avr97chbqgt70D_Zdstlu0SVOtF2MAbUgmDVxUE8QLzZa-b5XIZudlW_mIR7FKuXduCFZSGJ79B5MEg3OWYM9jG/s1600/one_dollar-50%25.jpg" /></a>It is easy <strong>and legal</strong> to convert the appearance of Federal Reserve Notes in the <a href="http://goldenfed.blogspot.com/2012/04/golden-fed-money-via-golden-ratiomean.html#fold">manner described below</a>.</div><br />
Currently, Federal Reserve Notes exhibit an aesthetic proportion called "The Pell Ratio" (named after the mathematician, <a href="http://www.ask.com/web?gct=serp&qsrc=2417&o=100000031&l=dis&q=john+pell+mathematician" rel="">John Pell</a>). If we take the length of any note and divide it by its width (or height), then the outcome is approximately 2.35 (2.348 = 15.5 cm ÷ 6.6 cm). This proportional ratio is very close to the ratio of 2.414, also known as one plus the square root of two (1 + <span style="font-size: larger; white-space: nowrap;">√<span style="text-decoration: overline;"> 2 </span></span>).<br />
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The Pell series of numbers is: 0, 1, 2, 5, 12, 29, 70, 169, and so on...<br />
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These numbers can be derived by doubling the last number and adding it to the first. For example, twelve doubled and then added to five yields twenty-nine, (12 x 2) + 5 = 29. The proportional ratio of their growth rate can be found by dividing the last number into the previous number of this series, 169 ÷ 70 = 2.4142857142857. If we were to extend this series out further, we would find that the growth rate will more closely approximate one plus the square root of two (2.4142135623730951).<br />
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This "Pell" growth rate is NOT native to this planet. The <a href="http://www.ask.com/web?gct=serp&qsrc=2417&o=100000031&l=dis&q=fibonacci+series">Fibonacci series</a> and the Fibonacci growth rate (aka, the <a href="http://www.ask.com/web?qsrc=2352&gct=serp&o=100000031&l=dis&dm=&q=golden%20ratio%20the%20definition">golden ratio</a> of 1.618) IS native to Earth. How do I know this? Here's why....<br />
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The Golden Ratio, or golden mean, also known as the <a href="http://www.ask.com/web?qsrc=2352&gct=serp&o=100000031&l=dis&dm=&q=divine%20proportion">divine proportion</a>, is exhibited in certain properties of aesthetic perception and action circumspect to planet Earth's biology. Humpbacked whales sing in a diatonic scale. Western style music, of which the diatonic scale is founded on, is based on the golden ratio whether it is a pure temperament or equal temperament scale. Pythagoras and modern-day <a href="http://www.ask.com/web?gct=serp&qsrc=2417&o=100000031&l=dis&q=golden+ratio+in+music">students of music discover this correlation</a>. But it gets better...<br />
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The atomic weight of a <a href="http://www.chem.qmul.ac.uk/iupac/AtWt/table.html" target="_blank">chloride ion</a> (35.45) divided by the atomic weight of a <a href="http://en.wikipedia.org/wiki/Sodium">sodium ion</a> (22.9898) is 1.542. You may say that is not 1.618, but Mother Nature doesn't need to be precise when it comes to planetary aesthetic themes. The study of aesthetics, as far as Nature is concerned, is more inclined towards <em>approximations</em> and the infinite variety of variant approximations, and less inclined towards precision or speed of computation. It's as if She is saying, "Hey dude, enjoy the ride and sniff a few flowers along the way." These properties of easy-goingness and non-exactness is exhibited in the <a href="http://en.wikipedia.org/wiki/Lucas_numbers">Lucas numbers</a>. In the Lucas series, a slight flaw is interjected at the very beginning of the Fibonacci series, and then the remainder of the series is built up in a Fibonacci fashion. So, instead of starting out with zero followed by one and proceeding onwards from there as the Fibonacci sequence exhibits, (namely: 0 + 1 = 1, 1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8, etc) the Lucas series starts out with the number two followed by the number one and builds on that. In other words: 2 + 1 = 3, 1 + 3 = 4, 3 + 4 = 7, 4 + 7 = 11, and so on.<br />
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Anyway, sodium chloride is the predominant salt within the bloodstream of all sentient creatures on this planet Earth and Earth's oceans. But if we look at other planets, just within our solar system, other salts are in evidence. On Venus, dipotassium phosphate is on its surface (K<sub>2</sub>HPO<sub>4</sub>). If Venus were to develop a biosphere inhabitable for life within the confines as we know it, then dipotassium phosphate would be available for biology to incorporate into its makeup as its dominant salt of choice and define its creature's sense for aesthetic proportion. By the way, the <a href="http://www.chem.qmul.ac.uk/iupac/AtWt/table.html" target="_blank">atomic weight</a> of two ions of potassium plus one of hydrogen (the dipotassium/hydrogen of that salt, namely: K<sub>2</sub>H = (K<sub>2</sub>:39.098 x 2) + H:1.008 = 79.204) when divided into the atomic weight of an ion of phosphate (PO<sub>4</sub> = P:30.974 + {O<sub>4</sub>:15.999 x 4} = 94.97), yields one-half of the Pell ratio (1.199 is one-half of 2.398). And since ratios can be reciprocals of one another and still be the same ratio, then it doesn't matter which way we interpret this deviation of the Pell ratio (as being either one-half of the Pell ratio, or twice the value of the reciprocal of the Pell ratio). This is because a ratio is the growth rate between any two values in a number series, or it can be an aesthetic proportion exhibited between any two measurements of an object, or it can be an aesthetic proportion exhibited between any two measurements of a sensory experience, and from the point of view of either value – one or the other. So if, <span style="background-color: yellow;">eight divided by five</span> yields 1.6, then its reciprocal relation of <span style="background-color: yellow;">five divided by eight</span> yields 0.625 – not precisely the same, but equivalent to one decimal digit to the right of the decimal point. This is good enough for an approximation generated by two adjacent numbers of the Fibonacci series towards the beginning of the series (namely: 0, 1, 1, 2, 3, <span style="background-color: yellow;">5, 8,</span> 13, 21, 34, 55, <span style="background-color: lime;">89, 144,</span> 233, 377, 610, etc), as compared to further out in the series, namely: <span style="background-color: lime;">144 ÷ 89</span> = 1.617. And when compared with its reciprocal relation of <span style="background-color: lime;">89 ÷ 144</span> = 0.618, then this is accurate to two decimal digits. So conversely, 94.97 (the atomic weight of the phosphate ion) divided into 79.204 (the atomic weights of dipotassium and hydrogen ions) yields 0.834. 0.834 is twice the value of the reciprocal of 2.398, namely: one divided by 2.398 is 0.417. And 0.417 times two is 0.834.<br />
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Let's take another planet, Mars. Mars is littered with calcium sulphate, <a href="http://en.wikipedia.org/wiki/Calcium_sulfate">CaSO<sub>4</sub></a>, which generates the atomically weighted proportion of 2.4 ({S:32.06 + [O<sub>4</sub>:15.999 x 4]} ÷ Ca:40.078 = 2.3967). Calcium sulphate is not known to be an ionic salt, but you get the picture. On Maldek (what's left of it is a mere asteroid belt between Mars and Jupiter), my hypothesis is a salt of <a href="http://www.ask.com/web?gct=serp&qsrc=2417&o=100000031&l=dis&q=sodium+ammonium+sulphate">sodium ammonium sulphate</a>, NaNH<sub>4</sub>SO<sub>4</sub> ({SO<sub>4</sub> = 96.056 = S:32.06 + [O<sub>4</sub>:15.999 x 4]} ÷ {NaNH<sub>4</sub> = 41.029 = Na:22.99 + N:14.007 + [H<sub>4</sub>:1.008 x 4]} = 2.341). Examples of sulphate salts exhibiting the Pell ratio on various planets seem to be so common, that the universe may be chuck-full of them! Ferrous Magnesium Sulphate, FeMg(SO<sub>4</sub>)<sub><span style="font-size: x-small;">2</span></sub>, is another possibility. I'll let you <a href="http://www.chem.qmul.ac.uk/iupac/AtWt/table.html" target="_blank">figure out its approximation</a> of the Pell ratio. I'm too lazy to do it here...<br />
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For the purposes of this discussion, Maldek strikes my fancy. My hypothesis is this....<br />
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What if a small portion of the Earth's inhabitants hail from this planet and they comprise the civilized countries of this Earth and dominate this planet with many of their cultural idiosyncrasies which are foreign to this Earth? And what if they couldn't handle life on their own planet due to <a href="http://www.youtube.com/watch?v=3szooXjhEGI" target="_blank">their own destructive tendencies which resulted in them destroying it</a> a long time ago? And what if the <span style="background-color: white;">consciousness of the Moon invited them to reincarnate there, but their destructive tendencies surfaced again resulting in their <a href="http://www.youtube.com/watch?v=Y-VMfzO94M0" target="_blank">blowing off the Moon's atmosphere</a> making it a dead planet to this day? And what if they then came to Earth during the third root race of Atlantis and were known as the "grey people" since the grey aliens living on the Moon at that time gave the reincarnated humans their grey bodies and the Moon was then a living biosphere? And what if the grey aliens still live on the Moon but they are sequestered within <em>artificial</em> biospheres? Pretty interesting possible historical narrative, don't you agree?</span><br />
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It is known that many Renaissance artists, including Leonardo da Vinci, used both the Pell and Golden ratios in their artwork. But this would make sense since they remember what is customarily aesthetically appealing to them. But I wonder......<br />
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What if it is improper to impose a ratio which is foreign to this planet, and foreign to all biology and aesthetic sensibilities among all of Earth's creatures?<br />
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<a href="http://goldenfed.blogspot.com/2012/04/golden-fed-money-via-golden-ratiomean.html#fold" name="fold">My suggestion</a> is a non-destructive one, namely: fold the two ends of each Federal Reserve Note over to its backside (and include a good sharp crease using the thumbnail against the side of the forefinger) in such a way that its length is reduced down to an appropriate length more closely approximating the proportions of a <a href="http://www.ask.com/web?qsrc=2352&gct=serp&o=100000031&l=dis&dm=&q=golden%20rectangle">Golden Rectangle</a> in which the length divided by the height is approximately 1.618.<br />
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It turns out that our job is very easy for the one and five dollar denominations. Here's my plan....<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhp0zGDBp0V7UGuacph0eUq0OVADUOYXHtKhiyDDvwcobVhShLQfS1GdHYdq6s3V13BBLlVlUuushIyQdOzCzV7bGurBJ3jAWjBGIFwxQY4Z4HR3AXk-iEJBeMutX0ekx00gu4s_MvPSZFC/s1600/one_dollar.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhp0zGDBp0V7UGuacph0eUq0OVADUOYXHtKhiyDDvwcobVhShLQfS1GdHYdq6s3V13BBLlVlUuushIyQdOzCzV7bGurBJ3jAWjBGIFwxQY4Z4HR3AXk-iEJBeMutX0ekx00gu4s_MvPSZFC/s1600/one_dollar.jpg" /></a></div><br />
Take a one dollar note out of your pocket and fold it in the manner shown above. I asked a banker to explain their requirements to me.... It has to be at least one-half as long as the original, and both serial numbers have to be visible. But this was if I had cut off the two ends. This would have been another example of a destructive tendency carried over from Maldek, namely: cutting up stuff. We don't want to repeat the mistakes of our past, now, do we? Hardly.... So, fold – don't mutilate – the two ends over towards the backside at these two points. But if you must destroy a little, then make one or more tiny tears into the crease to help hold them in place!<br />
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1. The left fold should be immediately <em>after</em> the first alpha-digit of the left-most serial number and <em>before</em> the first numeric-digit immediately following a space-break between these two digits. In this example pictured above, this left-most fold would be immediately after the capital "E" at the left-end of the left set of serial numbers within the space-break immediately before the "10768821 A".<br />
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2. The right fold should be immediately <em>after </em>the right-most serial number including all of its digits. In this example, the right fold would be immediately after the capital "A" at the end of the whole right set of serial numbers.<br />
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See how easy the Federal Reserve has made this for us? It's as if they purposely inserted a subliminal golden ratio within the confines of a one dollar bill within the context of a predominating Pell ratio defining its outer dimensions of height and length. A subliminal golden ratio is also inserted very conveniently within their five dollar bills in a slightly different manner....<br />
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<div class="separator" style="clear: both; text-align: center;"><a href="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi8UUivpuuHMg_UwTfxtgJTUXm-Q0-nBIu5iJ4l0nJog7pAB_ZB7wXDxWE_7buXE7Va1DnTpafXPj-jKv0YPCoSejStHSnLyZNg2olON-KkwNo9db7izj8nfj01V40uAsungMUAODKwLlzB/s1600/five_dollars.jpg" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi8UUivpuuHMg_UwTfxtgJTUXm-Q0-nBIu5iJ4l0nJog7pAB_ZB7wXDxWE_7buXE7Va1DnTpafXPj-jKv0YPCoSejStHSnLyZNg2olON-KkwNo9db7izj8nfj01V40uAsungMUAODKwLlzB/s1600/five_dollars.jpg" /></a></div><br />
1. Fold the left-end immediately <em>after</em> the first two alpha-digits and immediately <em>before</em> the numeric-digits which follow after a space-break between these two sets of numbers within the left serial number. In this example pictured above, the fold would be within the space after the "IL" and before the "25025502 C".<br />
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2. Fold the right-end immediately <em>before</em> the last alpha-digit at the end of the right set of serial numbers. In this example, this fold would be within the space-break immediately after the "IL 25025502" and before the capital letter "C".<br />
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So to repeat myself, these two denominations of one and five dollar bills are in the length of 15.5 cm (cm = centimeters). Their height is 6.6 cm. 15.5 cm divided by 6.6 cm is a ratio of approximately 2.348. So, we shorten down the length to around 10.7 cm (since 6.6 cm times 1.618 is 10.6788 cm). In these two photos above, it looks like the one dollar bill acquired a new length (when folded) of almost 10.6 cm; while the five dollar bill became slightly over 10.6 (the bill bent upwards slightly towards the camera, thus giving the appearance that it is slightly shorter than it really is).<br />
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See how easy this is!<br />
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Happy folding....Vinyasihttp://www.blogger.com/profile/15592343114620833464noreply@blogger.com0